-9v-4=5v^2

Solution for -9v-4=5v^2 equation:

-9v-4=5v^2

We move all terms to the left:

-9v-4-(5v^2)=0

determiningTheFunctionDomain
-5v^2-9v-4=0

a = -5; b = -9; c = -4;
Δ = b2-4ac
Δ = -92-4·(-5)·(-4)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-1}{2*-5}=\frac{8}{-10}
=-4/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+1}{2*-5}=\frac{10}{-10}
=-1
$